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Q.

The following figure shows a pentagonal-shaped park.


If Jyoti and Kavita were asked to find the area of the park, then what could be the area of the park?


Question Image

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a

337.5 m2

b

437.5 m2

c

338 m2

d

337 m2 

answer is A.

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Detailed Solution

The figure is,
Question Image
First, we will solve Jyoti's approach for solving the area of the pentagon.
The figure is divided into two trapeziums.
Question ImageGiven, AP = 30 m and BC = CD = DE = 15 m.
From figure,
CP + PD = CD = 15m   ------- (1)
Also, we will use formula,
Area of pentagon
= Area of trapezium ABCP + Area of trapezium AEDP
1 2 BC+AP CP+ 1 2 ED+AP PD 1 2 15+30 CP+ 1 2 15+30 PD   1 2 45 CP+ 1 2 45 PD 1 2 ×45 CP+PD  
Using equation (1), we will get,
22.5×CD 22.5×15 337.5  m 2   Next, we will solve Kavita's approach for solving the area of the pentagon.
The figure is divided into a triangle ABE and a rectangle BCDE.
Question Image Given, BE = BC = CD = DE = 15m and AP = 15m.
Also, we will use the formula,
Area of pentagon
= Area of triangle ABE + Area of rectangle BCDE
1 2 ×AP×BE + CD×BC   Substituting the values, we will get,
1 2 ×15×15 + 15×15  
112.5+225 337.5  m 2  
Thus, there may be many possibilities of dividing this given pentagon to find its area, but Joyti’s and Kavita’s diagrams are the two most-simple ways of solving it.
Hence, the area of the pentagon is 337.5 m2.
Thus, option (1) is correct.
 
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