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The following informations are available for the reaction: $R ⟶ P$
$\begin{array}{lll} R \to P; rate = r_{1} \\ R \overset{A}{\to} P; rate = r_{2} \\ R \overset{B}{⟶} P; rate = r_{3} \\ R \overset{C}{⟶} P; rate = r_{4} \\ R \overset{D}{⟶} P; rate = r_{5} \\ R \overset{A + C}{⟶} P; rate = r_{6} \\ R \overset{A + D}{⟶} P; rate = r_{7} \end{array}$
If $r_{3} < r_{1} = r_{4} = r_{5} < r_{7} < r_{2} < r_{6}$ , then the only incorrect statement is :

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B is inhibitor.

A is catalytic promotor of catalyst C

D is catalytic poison of catalyst A

C is catalytic promotor of catalyst A.

answer is D.

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Detailed Solution

A is a catalytic promotes of catalyst C.

$\begin{array}{l} R \to P; r ate = r_{1} \\ R \overset{A}{⟶} P; rate = r_{2} \\ R \overset{C}{\to} P; rate = r_{4} \\ R \overset{A + C}{\to} P; rate = r_{6} \\ r_{1} = r_{4} < r_{2} < r_{6} \end{array}$

$r_{1} = r_{y}$ so, C do not effect rate of reaction.

Hence, c is not a catalyst. $r_{1} < r_{2}$ implies that A is a catalyst. $r_{2} < r_{6}$ So, C is a catalyst promotes of catalyst A.

Hence, the answer is option D.

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