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Q.

The following is paramagnetic

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a

CaCl2
 

b

CuCl2

c

ZnCl2

d

NaCl

answer is B.

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Detailed Solution

(A) In CaCl2, Electronic configuration of Ca+2: [Ar] ; zero unpaired electrons, diamagnetic.

(B) In CuCl2, Electronic configuration of Cu+2: [Ar]3d9 ; one unpaired electron, para magnetic.

(C) In ZnCl2, Electronic configuration of  Zn+2: [Ar]3d10 ; zero unpaired electrons, diamagnetic.

(D) In NaCl, Electronic configuration of Na+: [Ne] ; zero unpaired electrons, diamagnetic.

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The following is paramagnetic