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The following is the distance-time table of a body in motion:

Time (s)
Distance (m)
Time (s)
Distance (m)
0
1
2
3
0
1
8
27
4
5
6
7
64
125
216
343

According to the table, the force on the object is

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Increasing with time

Decreasing with time

Constant

Data insufficient

answer is A.

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Detailed Solution

The force on the object is increasing with time.
From the table below, velocity and acceleration are calculated using formulas :

\Rightarrow v = \frac{s}{t}

\Rightarrow a = \frac{v - u}{t}

Time (s)

Distance (m)

Velocity (m/s)

Acceleration (m/s2)

125

216

343

In an equal interval of time, there is an unequal change in distance. As a result, the given object moves in a non-uniform motion. Because the object's velocity increases over time, so does its acceleration.

F \propto a

As a result, increasing acceleration indicates that the force acting on the object is also increasing.

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