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The following reagent react with glucose to form ester

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$HCN$

${({CH}_{3} CO)}_{2} O / {CH}_{3} COOH$

${NH}_{2} OH$

${[Ag {({NH}_{3})}_{2}]}^{+}$

answer is B.

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Detailed Solution

5 moles of Acetic anhydride react with one mole of glucose. One mole of glucose contains 5 moles of -OH groups.

Thus 5 moles of ester linkages are developed.Glucose penta acetate is formed.

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