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Q.

The following shows the time velocity graph for a moving object. The maximum acceleration will be

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a

$4 m / \sec^{2}$

b

$1 m / \sec^{2}$

c

$3 m / \sec^{2}$

d

$2 m / \sec^{2}$

answer is D.

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Detailed Solution

Slope of v – t graph gives acceleration

$a_{\max} = s l o p e o f B C a_{\max} = \frac{60 - 20}{40 - 30} = \frac{40}{10} = 4 m / s^{2}$

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