The following solutions were prepared by dissolving 10 g of glucose (C₆H₁₂O₆) in 250 ml of water (P₁), 10 g of urea (CH₄N₂O) in 250 ml of water (P₂) and 10 g of sucrose (C₁₂H₂₂O₁₁) in 250 ml of water (P₃). The right option for the decreasing order of osmotic pressure of these solutions is:

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P₃ > P₁ > P₂

P₂ > P₃ > P₁

P₂ > P₁ > P₃

P₁ > P₂ > P₃

answer is B.

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Detailed Solution

$Π= \frac{W}{M} ST π \propto \frac{1}{Mol . wt}$
Glucose (180), Urea (60), Sucrose (342)
$Π_{urea} > Π_{glucose} > Π_{sucrose}$
P₂ > P₁ > P₃

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