The following statement(s) are correct

The expression for 1^st order reaction is  $K=\frac{t}{2.303}\log \left[\frac{A_0}{A_t}\right]$

For a 1^st order reaction the degree of dissociation is equal to $\left(1-e^{-kt}\right)$ at any time ‘t’        

For a 1^st order reaction to obtain a positive slope a graph is plotted between $-{\log }_e\left[A\right]V_{S}t$           

The rate law for the reaction $H_2+I_2\to 2HI$ is $-2\frac{d}{dt}\left[H_2\right]=-2\frac{d}{dt}\left[I_2\right]=+\frac{d}{dt}\left[HI\right]$