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The following statements are true for Hofmann’s elimination except

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It is elimination of 3° amine to get anti- Saytzeff’s alkene.

If the alkyl groups are methyl groups, then methane is product

Alkene formed will be corresponding to alkyl group which has less number of carbon atoms except methyl group

If alkyl groups are methyl groups, then we get methyl alcohol

answer is B.

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Detailed Solution

Hofmann elimination reaction follows an E₂mechanism, where a quaternary ammonium salt is able to be removed from a hydrocarbon, resulting in an alkene product. This reaction results in the least substituted alkene being the primary product.

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