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The following table gives the data about motion of a van:

The speed of the van between $12.00$ hour and $12.30$ hour is $70 km h^{- 1}$ and the average speed of the car is ____ $km h^{- 1}$ .

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Detailed Solution

A distance-time graph depicts the motion of an object against time.
They are also known as displacement-time graphs.
The speed of the van between

12.00

hour and

12.30

hour is

70 km h^{- 1}

and the average speed of the car is

50 km h^{- 1}

.
Speed of a van between

12.00

hr and

12.30

hr =

70 km h^{- 1}

Total distance covered by the car =

100 km

And the total time =

13.00 - 11.00 = 2.0 h

Average speed of the car

v_{av}

\frac{100 km}{2.0 h}

\Rightarrow v_{av} = 50 km h^{- 1}

Motion of a car is not a uniform motion, as the s-t graph is not a single straight line.

https://lh6.googleusercontent.com/n4LImr61nxUnoEgi6SYJZx5mNfjDYea35mqPVwLvu9QNpxw-xZmFyYxRDKEtMFQVHMdXjXe4MT4jwM-8JaIuuCbSFkseXCt8T5BOkAuju2UCjjKwrUGl4pgU_Yhu_TbcFz5Fociul6mtyf0-jKB01vYGILvjR9fi4KazXzlL5k6R3LmHJzvfTm78LeDrgOyUaW3njA

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