The following table gives the production yield per hectare of wheat of 100 farms of a village.

Production yield (kg/ha)
Number of farms
50-55
2
55-60
8
60-65
12
65-70
24
70-75
38
75-80
16

The median of the given data using a 'more than type' distribution and its ogive will be:

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70.5

70.4

70.3

70.2

answer is D.

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Detailed Solution

Given table:

Production yield (kg/ha)	Number of farms
50-55	2
55-60	8
60-65	12
65-70	24
70-75	38
75-80	16

We have to find the median of the data using the more than type ogive graph.
The frequency table of the given data:

Production yield (kg/ha)	Number of farms
More than 50	2+8+12+24+38+16=100
More than 55	8+12+24+38+16=98
More than 60	12+24+38+16=90
More than 65	24+38+16=78
More than 70	38+16=54
More than 75	16

We will first calculate the value of N,

∴ N = 1002 = 50

To draw the more than ogive graph of the data, we will take the upper class limits of class interval on x-axis and their respective frequencies on y-axis and consider the point N w.r.t. x-axis.
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