The following two reactions of ${\mathrm{HNO}}_3$ with Zn are given as ( equations are not balanced)

$\begin{array}{r}\mathrm{Zn}+\text{ conc. }{\mathrm{HNO}}_3⟶\mathrm{Zn}{\left({\mathrm{NO}}_3\right)}_2+\mathrm{X}+{\mathrm{H}}_2\mathrm{O} ..\left(\mathrm{i}\right)\\ \mathrm{Zn}+\text{ dilute }{\mathrm{HNO}}_3⟶\mathrm{Zn}{\left({\mathrm{NO}}_3\right)}_2+\mathrm{Y}+{\mathrm{H}}_2\mathrm{O} ..\left(\mathrm{ii}\right)\end{array}$

In reactions (i) and (ii), the compounds X and Y respectively, are?

 

Given reactions are,

$\begin{array}{r}\mathrm{Zn}+\text{ conc. }{\mathrm{HNO}}_3⟶\mathrm{Zn}{\left({\mathrm{NO}}_3\right)}_2+\mathrm{X}+{\mathrm{H}}_2\mathrm{O} ..\left(\mathrm{i}\right)\\ \mathrm{Zn}+\text{ dilute }{\mathrm{HNO}}_3⟶\mathrm{Zn}{\left({\mathrm{NO}}_3\right)}_2+\mathrm{Y}+{\mathrm{H}}_2\mathrm{O} ..\left(\mathrm{ii}\right)\end{array}$

Now, when the Zn reacts with concentrated ${\mathrm{HNO}}_3$, then the resulting reaction takes place as

$\mathrm{Zn}+4{\mathrm{HNO}}_3\to \mathrm{Zn}{\left({\mathrm{NO}}_3\right)}_2+2{\mathrm{NO}}_2+2{\mathrm{H}}_2\mathrm{O}$

Now, again, when Zn reacts with the dilute ${\mathrm{HNO}}_3$ the reaction takes place as,

$4\mathrm{Zn}+10{\mathrm{HNO}}_3\to 4\mathrm{Zn}{\left({\mathrm{NO}}_3\right)}_2+{\mathrm{N}}_2\mathrm{O}+5{\mathrm{H}}_2\mathrm{O}$

On comparing it with the given equations we get,

$$\begin{gathered} \mathrm{X}={\mathrm{NO}}_2 \\ \mathrm{Y}={\mathrm{N}}_2\mathrm{O} \end{gathered}$$