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Q.

The force acting on each pole of a magnet when placed in a uniform magnetic field of 7A/m is 4.2 × 10^–4 N. If the distance between the poles is 10 cm, the moment of the magnet is

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a

$\frac{15}{π}$

b

7.5 × 10^–12Am²

c

$\frac{π}{15} {Am}^{2}$

d

6×10^–6Am²

answer is A.

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Detailed Solution

$F = \frac{M}{2 l} (μ_{0} H)$

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