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The force acting per unit length when a very long straight conductor is carrying a steady current of 1" " A and the direction of the current is from south to north is
(The horizontal component of the earth's magnetic field at the place is $3 \times 10^{- 5} T$ and the direction of the field is from the geographical south to geographical north.)

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$3 \times 10^{- 5} {Nm}^{- 1}$

$1 \times 10^{- 5} {Nm}^{- 1}$

$0$

$1.5 \times 10^{- 5} {Nm}^{- 1}$

answer is C.

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