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The force between two $α$ –particles separated by a distance ‘r’ is F. In order to have same force F, the distance between singly ionized chlorine atoms separated by a distance of:

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r/2

r/4

answer is C.

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Detailed Solution

$\begin{array}{rcl} F & = & \frac{1}{4 {πε}_{0}} \frac{2 e \times 2 e}{r^{2}}; \\ F_{2} & = & \frac{1}{4 {πε}_{0}} \frac{e \times e}{r_{2}^{2}} \end{array}$
But given

$\begin{array}{rcl} F_{2} & = & F; \\ r_{2}^{2} & = & \frac{r}{4} \\ \Rightarrow & r_{2} = \frac{r}{2} \end{array}$

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