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The force exerted by sun light of intensity 1350 ${Wm}^{- 2}$ reflected from a reflecting surface of an aluminum sheet of area $10^{4} m^{2} is$

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An Intiative by Sri Chaitanya

0.18 N

45 N

0.72 N

0.09 N

answer is B.

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Detailed Solution

Radiation pressure $P_{t} = \frac{2 I}{c}$

F = P $\times$ A= $\frac{2 I A}{C}$ =0.09 N

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