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The force experienced by a magnetic pole of strength 10A-m kept at a distance of 20cm from the centre of a short magnet of magnetic moment 10Am² on its axial line is

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0.0025N

0.25N

0.05N

0.005N

answer is A.

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Detailed Solution

$F = mB = \frac{10 \times 10^{- 7} \times 2 \times 10}{{(20 \times 10^{- 2})}^{3}} = 0 .0025 N$

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