Q.

The force F acting on a body moving along x-axis varies with the position x of the particle as shown in the graph. The body is in stable equilibrium at 

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a

both x1 and x2 

b

neither x1 nor x2

c

x=x1

d

x=x2

answer is B.

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Detailed Solution

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If d2Udx2>0, then it is the position of stable equillibriumIf d2Udx2<0, then it is the position of unstable equillibriumAt x1, dFdx>0ddxdUdx>0, i.e., d2Udx2<0x1 is the position of unstable equillibriumAt x2, dFdx<0ddxdUdx<0, i.e., d2Udx2>0x2 is the position of stable equillibrium

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