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The force F in newton acting on a bullet is given by $F = 6 - 2 t$ where t is in seconds. The net impulse imparted to the bullet in first three seconds is

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3 Ns

6 Ns

9 Ns

12 Ns

answer is C.

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Detailed Solution

$J = \int Fdt = \int (6 - 2 t) dt = 6 {[t]}_{o}^{3} - {[t^{2}]}_{o}^{3}$

= $6 (3) = (3^{2} - 0^{2}) = 9 Ns$

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