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Q.

The force is given in terms of time t and displacement x by the equation $F = A \cos B x + C \sin D t$ . The dimensional formula of $\frac{A D}{B}$ is

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a

$M^{2} L^{2} T^{- 3}$

b

$M^{0} L T^{- 1}$

c

$M L^{2} T^{- 3}$

d

$M^{1} L^{1} T^{- 2}$

answer is B.

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Detailed Solution

$A = M L T^{- 2}$

$B = L^{- 1}$

$D = T^{- 1}$

$∴ \frac{A D}{B} = M L^{2} T^{- 3}$

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