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The force on a body executing SHM is 2N when the displacement is 2cm. If the amplitude of oscillations is 5cm, what is the total energy associated with the SHM ?

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$1.25 \times 10^{- 2} J$

$125 \times 10^{- 2} J$

$12.5 \times 10^{- 2} J$

$0.125 \times 10^{- 2} J$

answer is C.

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Detailed Solution

$F = - Kx here F = 2 N and x = 2 \times 10^{- 2} m$

$substiuting K = 100 N / m total energy = \frac{1}{2} {KA}^{2} amplitude A = 5 \times 10^{- 2} m$

$total energy = \frac{1}{2} {KA}^{2} = \frac{1}{2} \times 100 \times 25 \times 10^{- 4} = 12.5 \times 10^{- 2} J$

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