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Q.

The force per unit length on a wire carrying current of 8A making an angle of 30∘ with a uniform magnetic field of 0.15 T is

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a

1.02 N

b

1.2 N

c

2.4 N

d

0.6 N

answer is C.

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Detailed Solution

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Magnetic force per-unit length,

F=BILsin⁡θ

F/l=BIsin⁡θ=0.15×8×0.5=0.6Nm−1

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