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The force required to drive a car at constant velocity is directly proportional to velocity. If it requires 300 W to drive a car with a velocity of $9 m s^{- 1}$ , the power it required to drive the car with a velocity of $36 m s^{- 1}$ is

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900 W

4800 W

1200 W

640 W

answer is B.

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Detailed Solution

P = FV as $F \propto V$

$P \propto V^{2}$

$\frac{300}{x} = \frac{9 \times 9}{\underset{4}{36} \times \underset{4}{36}}$

$X = 16 \times 300 = 4800 W$

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