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The formation of O^2- (g) starting from O(g) is endothermic by 603 kJ mol^-1. If electron affinity of O(g) is—141 kJ mol^-1, the second electron affinity of oxygen would be

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603 kJ mol^-1

+744 kJ mol^-1

-744 kJ mol^-1

-603 kJ mol^-1

answer is D.

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Detailed Solution

$O (g) + 2 e^{-} \to O^{2 -} (g), ΔH = 603 kJ {mol}^{- 1} . . . . (i) O (g) + e^{-} \to O^{-} (g), ΔH = - 141 {kJmol}^{- 1} . . . . . (ii)$

(i) - (ii) gives :

$O^{-} + e^{-} \to O^{2 -}, ΔH = 603 - (- 141) = 744 kJ {mol}^{- 1}$

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