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The formation of oxide ion from $O^{2 -} (g)$ requires first an exothermic and then an endothermic step as shown below
$O (g) + e^{-} \to O^{-} (g); Δ H^{0} = - 142 k J / m o l$
$O^{-} (g) + e^{-} \to O^{2 -} (g); Δ H^{0} = 844 k J / m o l$
This is because

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$O^{-}$ ion will tend to resist the addition another electron

Oxygen has high electron affinity

Oxygen has high electronegativity

$O^{-}$ ion has comparatively larger size than oxygen atom

answer is A.

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EA is an endothermic process

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