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Q.

The formation of the oxide ion,  O2(g), from oxygen atom requires first an exothermic and then an

 endothermic step as shown below: 

O(g)+eO(g);ΔegH=141kJmol1

O(g)+eO2(g);ΔegH=+780kJmol1

Thus process of formation of  O2 in gas phase is unfavorable even O2 is isoelectronic with neon. It is due to the fact that: 

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a

Oxygen is more electronegative

b

Addition of electron in oxygen results in larger size of the ion

c

Electron repulsion outweighs the stability gained by achieving noble gas configuration

d

O    ion has comparatively smaller size than oxygen atom.

answer is C.

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Detailed Solution

Process of formation of O2 ion in gaseous phase is unfavorable because O ion (anion) resists addition of another e due to repulsion hence, electron repulsion outweighs the stability gained by achieving noble gas configuration.

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The formation of the oxide ion,  O2−(g), from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g)+e−→O−(g); ΔegH=−141 kJ mol−1O−(g)+e−→O2−(g); ΔegH=+780 kJ mol−1Thus process of formation of  O2− in gas phase is unfavorable even O2− is isoelectronic with neon. It is due to the fact that: