The formation of ${\mathrm{O}}_2^{+}{\left[{\mathrm{PtF}}_6\right]}^{-}$ is the basis for the formation of xenon fluorides. This is because

The first ionization energies of Xe and O are 1170 kJ/mol and 1180 kJ/mol. Also both atoms have comparable sizes. Barlett is the person who prepares the complex, ${\left[{\mathrm{O}}_2\right]}^{+}{\left[{\mathrm{PtCl}}_6\right]}^{-}$, states that Xe also forms the similar compound with [PtCl₆] because of having comparable atomic size and ionization energy with O atom.