The formula for potassium permanganate is:

Potassium permanganate, ${\mathrm{KMnO}}_4$ is soluble in water and consists of two ions: a permanganate ion (${\mathrm{MnO}}_4^{-}$) and a potassium ion (${\mathrm{K}}^{+}$). 

In its physical state, it is a dark purple odourless solid. When potassium permanganate crystals are dissolved in water, the resulting solution is purple. It is considered a strong oxidizing agent and does not produce toxic by-products. It is usually prepared from manganese oxide by mixing a solution of KOH with oxidizing agents like potassium chlorate.  

$\begin{array}{rcl}6\mathrm{KOH}+3{\mathrm{MnO}}_2+6{\mathrm{KClO}}_3& \to & 3{\mathrm{K}}_2{\mathrm{MnO}}_4+6\mathrm{KCl}+3{\mathrm{H}}_2\mathrm{O}\end{array}$

This forms the potassium manganate (green) that is boiled with a large quantity of water. Then, current of chlorine, CO₂ , and ozonized air is passed through the liquid until manganate is converted into permanganate.

$6{\mathrm{K}}_2{\mathrm{MnO}}_4 + 3{\mathrm{Cl}}_2 \to \underset{\mathrm{Potassium} \mathrm{Permanganate}}{6{\mathrm{KMnO}}_4 }+ 6\mathrm{KCl}$

Hence, option 2 is the correct option.