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The formula of the complex tris (ethylenediamine) cobalt (lll) sulphate is

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$[Co {(en)}_{3} {SO}_{4}]$

${[Co {(en)}_{3}]}_{2} {({SO}_{4})}_{3}$

$[Cr {(en)}_{3}] {Br}_{3}$

${[Co {(en)}_{3}]}_{2} {SO}_{4}$

answer is D.

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Detailed Solution

[Co(en)₃]₂(SO₄)₃

→ Oxidation of en=0 SO₄ = −2, then we get Co = +3 as given

→ And tris is used as two numbers are present at that same spot.

→ where 2 is called "di" and 3 is called "tris".

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