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The formulae of the soluble complexes formed during the extraction of Ag and Au by the cyanide process respectively are

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$Na [Ag (CN)_{2}] and Na [Au (CN)_{2}]$

${Na}_{2} [Ag {(S_{2} O_{3})}_{4}] and H [{AuCl}_{4}]$

${Na}_{2} [{AgCN}_{4}] and {Na}_{4} [{Au}_{6} (CN)_{5}]$

${Na}_{3} [Ag (CN)_{2}] and {Na}_{2} [Au (CN)_{4}]$

answer is A.

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Detailed Solution

${Ag}_{2} S + 4 NaCN ⇌ 2 Na [Ag (CN)] + {Na}_{2} S$

$4 Au + 8 KCN + 2 H_{2} O + O_{2} ⟶ 4 K [Au (CN)_{2}] + 4 KOH$

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