The free space inside a current carrying toroid is filled with a material of susceptibility 2×10−2. The percentage increase in the Value of magnetic field inside the toroid will be

χ=2×10−2; μr=1+χ=1.02 ;Binitial=μ0ni ; Bfinal=μ0μrniBfinal−BinitialBinitial×100=μr−11×100=0.02×100=2%

χ=2×10−2; μr=1+χ=1.02 ;Binitial=μ0ni ; Bfinal=μ0μrniBfinal−BinitialBinitial×100=μr−11×100=0.02×100=2%

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The free space inside a current carrying toroid is filled with a material of susceptibility $2 \times 10^{- 2}$ . The percentage increase in the Value of magnetic field inside the toroid will be

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$χ = 2 \times 10^{- 2}; μ_{r} = 1 + χ = 1.02;$

$B_{initial} = μ_{0} ni; B_{final} = μ_{0} μ_{r} ni$

$\frac{B_{final} - B_{initial}}{B_{initial}} \times 100 = \frac{μ_{r} - 1}{1} \times 100 = 0.02 \times 100 = 2 %$

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