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The freezing point depression constant $(K_{f})$ of benzene is $5.12 K k g m o l^{- 1}$ . The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is (rounded off upto two decimal places):

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0.40K

0.20K

0.80K

0.60K

answer is B.

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Detailed Solution

$\begin{array}{l} Δ T_{f} = K_{f} m \\ = 5.12 \times 0.078 \\ = 0.399 ≃ 0.40 K \end{array}$

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