The freezing point depression constant $(K_{f})$ of benzene is 5.12 K kg ${mol}^{- 1}$ . The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is (rounded off up to two decimal places):

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0.40 K

0.20 K

0.60 K

0.80 K

answer is B.

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Detailed Solution

$\begin{aligned} K_{f} = 5 .12 K {kgmol}^{- 1} \\ {ΔT}_{f} = ? m = 0 .078 m \\ {ΔT}_{f} = K_{f} \times m \\ = 5 .12 \times 0 .078 \\ = 0 .399 = 0 .40 K \end{aligned}$

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