The freezing point of a solution composed of 10.0 g of KCl in 100 g of water is -4.5^oc. Calculate the van't Hoff factor i, for this solution.(K_f=1.86K kg mol^-1) [report answer to the nearest integer value]

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Detailed Solution

${ΔT}_{f} = 0 - (- 4.5) = 4 . 5^{o} c m_{KCl} = \frac{10}{74.5} \times \frac{1000}{100} = 1.34 m {ΔT}_{f} = {iK}_{f} m i = \frac{{ΔT}_{f}}{K_{f} m} i = \frac{4.5}{1.86 \times 1.34} = 1.805 ≅ 2$

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