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Q.

The freezing point of aqueous solution that contains 3% urea, 7.45% KCl and 9% of glucose is (given K, of water = 1.86 and assume molality = molarity). 

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a

266 K 

b

285.5 K 

c

250 K 

d

290 K 

answer is C.

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Detailed Solution

weight of solvent =100−3−7.45−9

=80.55 g

ΔTf=360+2×7.4574.5+918080.55×1000×1.86=6.93KTf=273−6.93=266K

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