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The freezing point of benzene decreases by ${0.45}^{0} C$ when 0.2g of acetic acid is added to 20g of benzene. If acetic acid associataed to form a dimer in benzene, percentage of association of acetic acid in benzene will be ( $K_{f}$ for benzene=5.12 K $K g m o l^{- 1}$ )

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$64.6 %$

$80.4 %$

$74.6 %$

$94.6 %$

answer is D.

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Detailed Solution

$Δ t_{f} = i K_{f} m α = \frac{1 - i}{1 - 1 / n}$

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