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The freezing point of benzene decreases by $0 . 45^{0} C$ when $0.2 g$ of acetic acid is added to $20 g$ of benzene. If acetic acid associated to from a dimer in benzene, percentage association of acetic acid in benzene will be ( $K_{f}$ for benzene $= 5.12 K {kgmol}^{- 1}$ )

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$80.4 %$

$64.6 %$

$94.6 %$

$74.6 %$

answer is D.

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Detailed Solution

$Δ T_{f} = {iK}_{f} m; 1 - \frac{α}{2} = i$

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