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Q.

The freezing point of one molal NaCl solution assuming NaCl to be 100% dissociated in water is (molal depression constant = 1.86)

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a

$+ {3.72}^{o} C$

b

$- {3.72}^{o} C$

c

$- {1.86}^{o} C$

d

$+ {1.8}^{o} C$

answer is B.

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Detailed Solution

For NaCl, $i = 2$

$\begin{array}{l} {ΔT}_{f} = 2 K_{f} m = 2 \times 1 .86 \times 1 = 3 .72 \\ T_{s} = T_{0} - {ΔT}_{f} = 0 - 3 .72 = - 3 {.72}^{o} C \end{array}$

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