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The frequencies of three tuning forks A, B and C have a relation n_A > n_B > n_C. When the forks A and B are sounded together the number of beats produced is $n_{1}$ . When A and C are sounded together the number of beats produced is $n_{2}$ , then the number of beats produced when B and C are sounded together is

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n₁ + n₂

$\large \frac{{{n_1} + {n_2}}}{2}$

n₂ – n₁

n₁ – n₂

answer is C.

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Detailed Solution

$\large {n_A} - {n_B}\, = \,{n_1}$

$\large {n_A} - {n_c}\, = \,{n_2}$

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