The frequency of a light wave in a material is 2×1014 Hz and wavelength is 5000 A0 . The refractive index of material will be

n=cv=cλf=3×1085000×10-10×2×1014=3

The frequency of a light wave in a material is 2×1014 Hz and wavelength is 5000 A0 . The refractive index of material will be

n=cv=cλf=3×1085000×10-10×2×1014=3

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The frequency of a light wave in a material is $2 \times 10^{14} Hz$ and wavelength is $5000 \overset{0}{A}$ . The refractive index of material will be

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1.40

1.50

3.00

1.33

answer is C.

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$n = \frac{c}{v} = \frac{c}{λ f} = \frac{3 \times 10^{8}}{5000 \times 10^{- 10} \times 2 \times 10^{14}} = 3$

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The frequency of a light wave in a material is 2×1014 Hz and wavelength is 5000 A0 . The refractive index of material will be

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The frequency of a light wave in a material is $2 \times 10^{14} Hz$ and wavelength is $5000 \overset{0}{A}$ . The refractive index of material will be