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The frequency of a particle performing SHM is 12 Hz. Its amplitude is 4 cm. Its initial displacement is 2 cm towards positive extreme position. Its equation for displacement is

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$x = 0 .04 \cos (24 πt + \frac{π}{6}) m$

$x = 0 .04 \sin (24 πt) m$

$x = 0 .04 \sin (24 πt + \frac{π}{6}) m$

$x = 0 .04 \cos (24 πt) m$

answer is C.

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$x = Asin (ωt + ϕ)$

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