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Q.

The frequency of one of the lines is Paschen series of hydrogen atom is 2.340  ×  1011Hz. The quantum number n2 which produces this transition is

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a

6

b

3

c

4

d

5

answer is B.

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Detailed Solution

v¯=1λ RH 1n12 −1n22 =1λ RH 132 −1n22    Since n1=3for  Paschen  series.   If  n2=5  then  v=2.340  ×  1014 Hz

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