Q.

The  frequency  of radiation  absorbed  or emitted when transition occurs  between two stationary states with energies  E1 (lower)  and  E2 (higher)  is given by

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a

v=E1+E2h

b

v=E2E1h

c

v=E1×E2h

d

v=E1E2h

answer is D.

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Detailed Solution

According to Bohr's postulates:

The frequency of radiation absorbed or emitted when transition occurs between two stationary states that differ in energy by ΔE, is given by:

ν=Eh =E2-E1h​​

Where E1​ and E2 are the energies of the lower and higher allowed energy states, respectively.

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