The frequency of radiation absorbed or emitted when transition occurs between two stationary states with energies E₁(lower) and E₂ (higher) is given by

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$v = \frac{E_{1} + E_{2}}{h}$

$v = \frac{E_{2} - E_{1}}{h}$

$v = \frac{E_{1} \times E_{2}}{h}$

$v = \frac{E_{1} - E_{2}}{h}$

answer is D.

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Detailed Solution

According to Bohr's postulates:

The frequency of radiation absorbed or emitted when transition occurs between two stationary states that differ in energy by ΔE, is given by:

ν= $\frac{∆ E}{h} = \frac{E_{2} - E_{1}}{h}$

Where E₁and E₂ are the energies of the lower and higher allowed energy states, respectively.

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