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The frequency of the characteristic x-ray of $K_{α}$ line of metal tanget M’ is $2500 c m^{- 1}$ and the graph between $\sqrt{ϑ} v_{s}$ ‘Z’ is as follows, then atomic number of M is

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answer is C.

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Detailed Solution

$\begin{array}{l} \sqrt{v} = K_{1} (Z - K_{2}) \\ \sqrt{v} = K_{1} Z - K_{1} K_{2} [[\begin{array}{l} m = K_{1} = Tan 45^{0} = 1 \\ OA = 1 K_{2} K_{1} = - 1 \end{array}] \\ y = mx + c \\ \sqrt{2500} = 1 \times Z - 1 \\ Z = 51 \end{array}$

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