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Q.

The frequency of the incident light falling on a photosensitive metal plate is doubled, the kinetic energy of the emitted photoelectrons is

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a

Double the earlier value

b

More than doubled

c

Unchanged

d

Less than doubled

answer is C.

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Detailed Solution

E=Wo+Kmax

Kmax=EWo=hvWo

K1=hvWo  and  K2=2hvWo

K2>2K1

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