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Q.

The frequency of whistle of an engine appears to be 45thof initial frequency when it crosses a stationary observer. If the velocity of sound is 330 m/s, then the speed of engine will be 

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a

30 m/s

b

330 m/s

c

36.6 m/s 

d

40 m/s

answer is B.

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Detailed Solution

n'=nvv-vs               .....(1)

n"=nvv+vs    ........(2)

From (1) and (2), n'n''=v+vsv-vs       .....(3)

According to question,n'n''=54

vs = ? v = 330 m/s                …………….(4)

From eq. (3) and (4)

54=330+vs330-vs

9vs = 330

 ∴ vs = 36.6 m/s

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