Q.

The friction coefficient between the table and the block shown in figure is 0.2. Find the tensions T1 and T2 in the two strings

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a

150 N, 50 N

b

90 N, 70 N

c

75 N, 75 N

d

96 N , 68 N

answer is A.

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Detailed Solution

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Let ‘a’ be acceleration of system

For 15 kg block, 150 – T1 = 15a (or)

T1 = 150 – 15a 

For 5 kg block, T2 - 50 = 5 a (or)

T2 = 50 + 5a 

For 5 kg block on table T1 – T2 – f = 5a

T1T2μmg=5a

T1T210=5a

On solving the equations,

T1=96N,T2=68N

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