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The frustum cone curved surface area is 600 $m m^{3}$ . The upper and lower circle area of a cone is 25 and 35 mm. Find the total surface area.

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660

m m^{3}

650

m m^{3}

560

m m^{3}

660

mm

answer is A.

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Detailed Solution

Given that,
Curved surface area of a frustum cone is 600

m m^{3}

.
The upper and lower circle area of a cone is 25mm and 35 mm.
Total surface area =

π (R + r) s + A_{1} + A_{2}

Curved surface area =

π (R + r) s

A_{1} = 25 mm, A_{2} = 35 mm

Therefore, total surface area = 600 + 25 + 35.
TSA = 660

m m^{3}

Hence, the correct option is 1.

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