The function f satisfies the functional equation 3f(x)+2fx+59x−1=10x+30 for all real x≠1. The value of f(7) is

3f(x)+2fx+59x−1=10x+30x=7,3f(7)+2f(11)=70+30=100x=11,3f(11)+2f(7)=140f(7)−20=f(11)−220=−19−4⇒f(7)=4

The function f satisfies the functional equation 3f(x)+2fx+59x−1=10x+30 for all real x≠1. The value of f(7) is

3f(x)+2fx+59x−1=10x+30x=7,3f(7)+2f(11)=70+30=100x=11,3f(11)+2f(7)=140f(7)−20=f(11)−220=−19−4⇒f(7)=4

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$The function f satisfies the functional equation 3 f (x) + 2 f (\frac{x + 59}{x - 1}) = 10 x + 30 for all real x \neq 1 . The value of f (7) is$

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$3 f (x) + 2 f (\frac{x + 59}{x - 1}) = 10 x + 30$

$x = 7, 3 f (7) + 2 f (11) = 70 + 30 = 100$

$\begin{array}{l} x = 11, 3 f (11) + 2 f (7) = 140 \\ \frac{f (7)}{- 20} = \frac{f (11)}{- 220} = \frac{- 1}{9 - 4} \Rightarrow f (7) = 4 \end{array}$

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The function f satisfies the functional equation 3f(x)+2fx+59x−1=10x+30 for all real x≠1. The value of f(7) is

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$The function f satisfies the functional equation 3 f (x) + 2 f (\frac{x + 59}{x - 1}) = 10 x + 30 for all real x \neq 1 . The value of f (7) is$