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The function of time representing a simple harmonic motion with a period of $\frac{π}{ω}$ is :

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$\sin (ω t) + \cos (ω t)$

$3 \cos (\frac{π}{4} - 2 ω t)$

$\sin^{2} (ω t)$

$\cos (ω t) + \cos (2 ω t) + \cos (3 ω t)$

answer is B.

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Detailed Solution

$y = 3 \cos (\frac{π}{4} - 2 ω t)$ $\Rightarrow y = 3 \cos (2 ω t - π / 4)$ It is in SHM
$T = \frac{2 π}{2 ω} = \frac{π}{ω}$
Or
$y = \sin^{2} x$ $= \frac{1}{2} - \frac{1}{2} \cos 2 (w t)$

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