Q.

The function of time representing a simple harmonic motion with a period of  πω  is :

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a

cos(ωt)+cos(2ωt)+cos(3ωt)

b

3cos(π42ωt)

c

sin(ωt)+cos(ωt)

d

sin2(ωt)

answer is B.

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Detailed Solution

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y=3cos(π42ωt)        y=3cos(2ωtπ/4)     It is in SHM
T=2π2ω=πω 
Or
y=sin2x               =1212cos2(wt)   

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